…I’d have to buy 7 packs of tortillas and 6 packs of cheese before coming close enough to matching 1:1 with only 1 cheese slice left at the end so just eat the last fucking cheese slice by itself.
And please don’t try to make too much sense of my diagram up there because I made 2 mistakes that only make sense to me & I don’t feel like explaining.
But what I REALLY want to know: If you’re aware of an algebraic method for solving this timeless hot dog bun vs hot dog conundrum, please share your wisdom.
So the ratio is 8:11, that means you flip it and multiple. 11 packs of tortillas get you 88 tortillas. 8 packs of cheese gets you 88 cheese. They don’t share a common denominator so that’s the lowest amount you can get without breaking a pack or getting spares.
If they do share a common denominator you can reduce. For instance 8buns and 10 hotdogs means 8:10 or 4:5 making the equivalent point 40 of each.

Not by height…the ratio you’re looking for is dick-to-floor or D2f
Mathematically you’re looking for the “least common multiple”, which is in this case 8x11 because 11 is prime, so 8 packs of cheese, and 11 packs of tortillas, for 88 of each.
In case you have something with a common divisor, like imagine you had cheese in 10-packs instead, you could get away with 40 of each, because 4x10 is 40 and 5x8 is also 40, so just 4 10-packs of cheese and 5 8-packs of tortillas would already mat©h up.
mat©h up
🤓
Ah yes this scratches my mathematical itch. Thank you.
You’re putting sliced cheese on a tortilla? Buy a block and shred it!
I did not ask for culinary advice. I asked for mathematical advice. You do whatever the fuck you want with your own food in your own kitchen. I do not have a kitchen or a cheese shredder.
It’s pretty harsh, bud.
Cheese shredders are not some high tech technology nor do they need a kitchen
I live in my car. Would you shred cheese in your car? You go ahead and do that, then come back and let me know how much fun that was.
I’ve shredded cheese when camping. Honestly, the only issue there should be storage of the cheese. In such a situation, typically I’d use a small knife to cut the cheese rather than buy precut
I mean, could you not just take 3 slices of cheese and divide them by 8, add those parts to the other 8.
Yes there are a million ways to go about this, but I was mathematically curious how long it would take until both would match up.
Because right now IRL I’ve got three slices of cheese with no more tortillas left to put them on 😭
I’d say you’d need 8 packs of cheese and 11 packs of tortillas
33 cheeses and 32 tortillas…?
Also 7x8=56 and 6x11=66, so you’d have 10 left over, not 1. What the hell were you smoking? You could eat a tortilla without a slice of cheese, though.
You’re right, my erroneous figuring came from counting the squares & circles I scrawled on that primitive diagram. That’s why I’m glad I came here for y’all to show me the real math & correct solution.
So 4 packs of tortillas & 3 packs of cheese would be the least I could buy to come closest to my 1:1 wish, with just one trivial thing left over.
Thank you!

